genfile()函数用来定义一个genrule()的输出文件
下面的例子里面,一个叫messenger_manifest用来在 ``buck-out/gen/ `` 目录下生成一个叫 ``AndroidManifest.xml ``的文件,这个文件是用来作为messager构建规则的messager。路径必须被gemfile函数包括,所以android_binary()用buck-out/gen里面的 `` AndroidManifest.xml ``而不是构建文件下的那个。
genrule(
name = 'messenger_manifest',
srcs = [
'update_manifest.py',
'AndroidManifest.xml',
],
cmd = 'python update_manifest.py AndroidManifest.xml > $OUT',
out = 'AndroidManifest.xml',
)
android_binary(
name = 'messenger',
manifest = genfile('AndroidManifest.xml'),
target = 'Google Inc.:Google APIs:16',
keystore_properties = 'keystore.properties',
deps = [
':messenger_manifest',
# Additional dependent android_library rules would be listed here,
# as well.
],
)